(4x^2+5x-4)/(2x+1)

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Solution for (4x^2+5x-4)/(2x+1) equation:


D( x )

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0 // - 1

2*x = -1 // : 2

x = -1/2

x in (-oo:-1/2) U (-1/2:+oo)

(4*x^2+5*x-4)/(2*x+1) = 0

4*x^2+5*x-4 = 0

4*x^2+5*x-4 = 0

DELTA = 5^2-(-4*4*4)

DELTA = 89

DELTA > 0

x = (89^(1/2)-5)/(2*4) or x = (-89^(1/2)-5)/(2*4)

x = (89^(1/2)-5)/8 or x = (-(89^(1/2)+5))/8

(x+(89^(1/2)+5)/8)*(x-((89^(1/2)-5)/8)) = 0

((x+(89^(1/2)+5)/8)*(x-((89^(1/2)-5)/8)))/(2*x+1) = 0

( x+(89^(1/2)+5)/8 )

x+(89^(1/2)+5)/8 = 0 // - (89^(1/2)+5)/8

x = -((89^(1/2)+5)/8)

( x-((89^(1/2)-5)/8) )

x-((89^(1/2)-5)/8) = 0 // + (89^(1/2)-5)/8

x = (89^(1/2)-5)/8

x in { -((89^(1/2)+5)/8), (89^(1/2)-5)/8 }

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